document.write( "Question 1152968: Mark made a business trip of 236 miles.He averaged 58mphfor the first part of the trip and 60mph for the second part.If the trip took 4 hours, how long did he travel at each rate?
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Algebra.Com's Answer #775109 by ikleyn(52811)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "This question \"how long did he travel at each rate?\" may relate to the distance and/or to the time.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Since it is not precisely determined in the post, I will assume that it relates to times.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Let \"t\" be the time spent traveling the first part.\r\n" ); document.write( "\r\n" ); document.write( "Then the time traveling second part is (4-t) hours.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "You have this single equation to find \"t\"\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 58*t + 60*(4-t) = 236 miles (total distance)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "From the equation\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 58*t - 60*t = 236 - 60*4\r\n" ); document.write( "\r\n" ); document.write( " -2t = - 4\r\n" ); document.write( "\r\n" ); document.write( " t =\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |