document.write( "Question 1152960: find the possible values of p if p-3,3p-5,18-5 are consecutive terms of a geometric progression. \n" ); document.write( "
Algebra.Com's Answer #775102 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "consecutive terms of a geometric progression \r
\n" ); document.write( "\n" ); document.write( "\"p-3\",\"3p-5\",\"18-5\"....not sure about third term, I guess you have \"18p-5\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "first express common ratio using given terms:\r
\n" ); document.write( "\n" ); document.write( "\"r=%283p-5%29%2F%28p-3%29\"\r
\n" ); document.write( "\n" ); document.write( "\"r=%2818p-5%29%2F%283p-5%29\"\r
\n" ); document.write( "\n" ); document.write( "\"r=r\"=>\r
\n" ); document.write( "\n" ); document.write( "\"%283p-5%29%2F%28p-3%29=%2818p-5%29%2F%283p-5%29\"\r
\n" ); document.write( "\n" ); document.write( "\"%283p-5%29%283p-5%29=%2818p-5%29%28p-3%29\"\r
\n" ); document.write( "\n" ); document.write( "\"9p%5E2-30p+%2B+25=18p%5E2-+59p+%2B+15\"\r
\n" ); document.write( "\n" ); document.write( "\"18p%5E2+-+59p+%2B+15-9p%5E2+%2B+30p+-25=0\"\r
\n" ); document.write( "\n" ); document.write( "\"9p%5E2+-+29p+-+10=0\"\r
\n" ); document.write( "\n" ); document.write( "use quadratic formula\r
\n" ); document.write( "\n" ); document.write( "\"p=%28-%28-29%29%2B-sqrt%28%28-29%29%5E2-4%2A9%2A%28-10%29%29%2F%282%2A9%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"p=%2829%2B-sqrt%28841%2B360%29%29%2F18\"\r
\n" ); document.write( "\n" ); document.write( "\"p=%2829%2B-sqrt%281201%29%29%2F18\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "exact solutions:\r
\n" ); document.write( "\n" ); document.write( "\"p=%2829%2Bsqrt%281201%29%29%2F18\" or
\n" ); document.write( "\"p=%2829-sqrt%281201%29%29%2F18\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );