document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1152942>Question 1152942</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ms. Thompson has written a log for her store every 3 months for the last 6 years. If 2/3 of the log shows the store earns more money than it spends.\r<BR>\n" );
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document.write( "1. How many logs show her store spending money than it earns? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #775070 by </B><A HREF=/tutors/aboutme.mpl?userid=josmiceli><B>josmiceli(19441)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josmiceli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josmiceli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=775070\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ( 12 months/year ) x ( 6 years ) = ( 72 months )<BR>\n" );
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document.write( "( 72 months ) / ( 3 months/ log ) = ( 24 logs )<BR>\n" );
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document.write( "( 24 logs ) x ( 2/3 ) = ( 16 logs ) earns more than spends<BR>\n" );
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document.write( "( 24 logs ) x ( 1/3 ) = ( 8 logs ) spends more than earns\r<BR>\n" );
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