document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1152889>Question 1152889</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A courier who goes at the rate of 4.5mi./h is followed, after 6.0h, by another who goes at the rate of 5.5mi./h. In how many hours will the second overtake the first x? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #775024 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=775024\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> At the time that the follower begins travel, the distance between the courier and the follower is  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4.5%2A6%2Ahours=27%2Amiles ALIGN=MIDDLE  ALT=\"4.5%2A6%2Ahours=27%2Amiles\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "Approach rate between the two is 1 mile per hour.\r<BR>\n" );
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document.write( "How many hours x, to overtake?\r<BR>\n" );
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