document.write( "Question 1152879: Solve this application problem using a system of equations: 6000 is invested, part of it at 20% and part of it at 4%. For a certain year, the total yield is $800.00. How much was invested at 20%? How much was invested at 4%? \n" ); document.write( "
Algebra.Com's Answer #775011 by ankor@dixie-net.com(22740)\"\" \"About 
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6000 is invested, part of it at 20% and part of it at 4%.
\n" ); document.write( " For a certain year, the total yield is $800.00.
\n" ); document.write( " How much was invested at 20%? How much was invested at 4%?
\n" ); document.write( ":
\n" ); document.write( "Let a = amt invested at 20%
\n" ); document.write( "the total amt invested is $6000, therefore
\n" ); document.write( "(6000-a) = amt invested at 4%
\n" ); document.write( ":
\n" ); document.write( ".20a + .04(6000-a) = 800
\n" ); document.write( ".20a + 240 - .04a = 800
\n" ); document.write( ".20a - .04a = 800 - 240
\n" ); document.write( ".16a = 560
\n" ); document.write( "a = 560/.16
\n" ); document.write( "a = $3500 invested at 20%
\n" ); document.write( "and
\n" ); document.write( "6000 - 3500 = $2500 invested at 4%
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this by finding the actual amt earned from each investment
\n" ); document.write( ".20(3500) = 700
\n" ); document.write( ".04(2500) = 100
\n" ); document.write( "----------------
\n" ); document.write( "earned total: 800 \n" ); document.write( "
\n" );