document.write( "Question 1152863: Hi
\n" ); document.write( "A box of sweets is shared between A B C in the ratio of 3:4:5 B receives 48 sweets.\r
\n" ); document.write( "\n" ); document.write( "C shares some of his sweets with his brothers. After sharing the ratio A B C is
\n" ); document.write( "12;16;15.\r
\n" ); document.write( "\n" ); document.write( "Find the number of sweets C shared with his brothers. \r
\n" ); document.write( "\n" ); document.write( "Thanks
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Algebra.Com's Answer #774999 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The ratio initially is A:B:C = 3:4:5, with B having 48 sweets.

\n" ); document.write( "Any number of different calculations can be done to determine that A has 36 sweets and C has 60 sweets; and the total number of sweets is 144.

\n" ); document.write( "After C shares some of his sweets with A and B, the ratio is supposed to be A:B:C = 12:16:15.

\n" ); document.write( "But 144 sweets can't be divided in the ratio 12:16:15 -- so the problem is flawed.

\n" ); document.write( "If the ratio shown at the end of the problem is correct, then C didn't share any of his sweets with his brothers -- he simply ate some of his.

\n" ); document.write( "\"12x%2B16x%2B15x+=+43x\"

\n" ); document.write( "x has to be an integer for which 43x is less than 144; the maximum value is 3. That means the numbers of sweets are now 36, 48, and 45.

\n" ); document.write( "So A and B still have the numbers they started with; and C has 15 fewer.

\n" ); document.write( "And since I don't think he would have thrown them away, my guess is he ate them....

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