document.write( "Question 1152863: Hi
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document.write( "A box of sweets is shared between A B C in the ratio of 3:4:5 B receives 48 sweets.\r
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document.write( "C shares some of his sweets with his brothers. After sharing the ratio A B C is
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document.write( "12;16;15.\r
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document.write( "Find the number of sweets C shared with his brothers. \r
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document.write( "Thanks \n" );
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Algebra.Com's Answer #774990 by ikleyn(52776)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "You are given that the original distribution of sweets was 3:4:5 between A, B and C.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "It means, in translation to human language, that A, B and C possessed 3x, 4x and 5x sweets, respectively,\r\n" ); document.write( "\r\n" ); document.write( "where x is the common measure of these quantities, now unknown.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "But, in addition, you know from the condition that 4x = 48 sweets that B had.\r\n" ); document.write( "\r\n" ); document.write( " Therefore, x = 48/4 = 12.\r\n" ); document.write( "\r\n" ); document.write( "Hence, A, B and C had initially 3x = 3*12 = 36 sweets, 4x = 4*12 = 48 sweets and 5*x = 5*12 = 60 sweets, respectively.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " Half of the problem is just solved. Now we should analyse the second half.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "After C shared his sweets with the brothers, the proportion became 12:16:15.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "It means that now A, B and C possess 12y, 16y, and 15y of sweets, respectively.\r\n" ); document.write( "\r\n" ); document.write( "Here y is the new common measure of their possessions, now unknown.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "But we know that A still has 36 sweets, from the first half of the solution.\r\n" ); document.write( "\r\n" ); document.write( "Hence, y = 36/12 = 3. It implies that after sharing C possess 15*y = 15*3 = 45 sweets.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Hence, 60-45 = 15 is the number of sweets C passed to his brothers. ANSWER\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |