document.write( "Question 1152772: An IQ test has a mean of 100 and a standard deviation of 15. Assume a normal distribution. Find the probability. \r
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Algebra.Com's Answer #774889 by VFBundy(438)\"\" \"About 
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z-score = \"%28IQ+-+mean%29%2FSD\" = \"%28125+-+100%29%2F15\" = 25/15 = 1.67
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\n" ); document.write( "Look up 1.67 on a z-table. The value is 0.9525. This is the probability someone scores LESS than 125. So, the probability someone scores MORE than 125 is the inverse, or 0.0475.
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