document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1152785>Question 1152785</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A manufacturing company regularly conducts quality control checks at specified periods on the products it manufactures.​ Historically, the failure rate for LED light bulbs that the company manufactures is 8​%. Suppose a random sample of 10 LED light bulbs is selected. Complete parts​ (a) through​ (d) below.<BR>\n" );
document.write( "a. What is the probability that none of the LED light bulbs are​ defective?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #774866 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=774866\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font color=black size=3><BR>\n" );
document.write( "This is a binomial problem. Each selection is independent of one another, and a bulb is either defective or it is not defective.\r<BR>\n" );
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document.write( "p = 0.08 is the probability of being defective<BR>\n" );
document.write( "1-p = 1-0.08 = 0.92 is the probability of not being defective<BR>\n" );
document.write( "n = 10 is the sample size\r<BR>\n" );
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document.write( "Use the Binomial PDF function<BR>\n" );
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document.write( "x is a non-negative whole number representing the number of defective bulbs\r<BR>\n" );
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document.write( "Plug in n = 10 and p = 0.08<BR>\n" );
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document.write( "Now plug in x = 0, which will help us find the probability of x = 0 bulbs being defective<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=B%280%29+=+%28%2810%21%29%2F%2810%21%29%29%2A%280.08%29%5E0%2A%280.92%29%5E10 ALIGN=MIDDLE  ALT=\"B%280%29+=+%28%2810%21%29%2F%2810%21%29%29%2A%280.08%29%5E0%2A%280.92%29%5E10\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=B%280%29+=+%280.92%29%5E10 ALIGN=MIDDLE  ALT=\"B%280%29+=+%280.92%29%5E10\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=B%280%29+=+0.434+388+454+223+63 ALIGN=MIDDLE  ALT=\"B%280%29+=+0.434+388+454+223+63\"   DISABLED_style= \"max-width:90%; height:auto;\" > Use your calculator. This value is approximate.\r<BR>\n" );
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document.write( "When rounded to 3 decimal places, the approximate answer is <font size=4 color=red>0.434</font><BR>\n" );
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