document.write( "Question 1152787: Hello please help with the following question-thanks so much \r
\n" ); document.write( "\n" ); document.write( "The area of a rectangle is 40 square units more than its length. The width is 6 units. What is the area?
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Algebra.Com's Answer #774859 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Area, \"A+=+L%2AW\"\r
\n" ); document.write( "\n" ); document.write( "Width \"W=6\"\r
\n" ); document.write( "\n" ); document.write( "Length, \"L=A-40+\"\r
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\n" ); document.write( "\n" ); document.write( "then\r
\n" ); document.write( "\n" ); document.write( "\"A+=+%28A-40+%29%2A6\"\r
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\n" ); document.write( "\n" ); document.write( "\"A+=+6A-240+\"\r
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\n" ); document.write( "\n" ); document.write( "\"240+=+6A-A\"\r
\n" ); document.write( "\n" ); document.write( "\"240+=+5A\"\r
\n" ); document.write( "\n" ); document.write( "\"A+=+240%2F5+\"\r
\n" ); document.write( "\n" ); document.write( "\"A+=+48+\"\r
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\n" ); document.write( "\n" ); document.write( "and, the length is \"L=48-40=8+\"\r
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