document.write( "Question 1152786: A committee of 6 U.S. senators is to be formed with 3 Democrats and 3 Republicans. In how many ways can this be done if there are 61 Democratic senators and 39 Republican senators? \n" ); document.write( "
Algebra.Com's Answer #774858 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "We will use the combination function
\n" ); document.write( "\"C%28n%2Cr%29+=+%28n%21%29%2F%28r%21%2A%28n-r%29%21%29\"
\n" ); document.write( "to count the number of ways to select members. We use the combination function (not the permutation function) because order does not matter when selecting a committee. Any member does not outrank another, and there are no special positions. All that matters is the group as a whole rather an any particular individual. \r
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\n" ); document.write( "\n" ); document.write( "Your book may use notation that looks like instead of \"C%28n%2Cr%29\", but its the same thing. \r
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\n" ); document.write( "\n" ); document.write( "The exclamation marks represent factorials. Writing something like \"6%21\" means \"6%21+=+6%2A5%2A4%2A3%2A2%2A1\" so we start at 6 and count our way down to 1 multiplying along the way.\r
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\n" ); document.write( "\n" ); document.write( "Note how something like \"4%21+=+4%2A3%2A2%2A1\" is fully contained inside of the expression for \"6%21\"\r
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\n" ); document.write( "\n" ); document.write( "This means, \r
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\n" ); document.write( "\n" ); document.write( "In short, \"6%21+=+6%2A5%2A4%21\"\r
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\n" ); document.write( "\n" ); document.write( "This will come in handy later on. Specifically the lines where I write \"use the factorial trick\" (see below). This is to cancel out factorials that would otherwise be massively large numbers.\r
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\n" ); document.write( "\n" ); document.write( "For the Democrats, we have n = 61 people to choose from and r = 3 slots to fill.
\n" ); document.write( "Use the combination function to figure out how many ways there are to do this.\r
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\n" ); document.write( "\n" ); document.write( "\"C%28n%2Cr%29+=+%28n%21%29%2F%28r%21%2A%28n-r%29%21%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"C%2861%2C3%29+=+%2861%21%29%2F%283%21%2A%2861-3%29%21%29\" Replace n with 61, replace r with 3\r
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\n" ); document.write( "\n" ); document.write( "\"C%2861%2C3%29+=+%2861%2A60%2A59%2A58%21%29%2F%283%21%2A58%21%29\" Use the factorial trick. We started at 61 and stop at 58 because of the 58! in the denominator.\r
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\n" ); document.write( "\n" ); document.write( " We have these highlighted terms pair up\r
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\n" ); document.write( "\n" ); document.write( "\"C%2861%2C3%29+=+%2861%2A60%2A59%2Across%2858%21%29%29%2F%283%21%2Across%2858%21%29%29\" and cancel out. A much simpler expression is left over \r
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\n" ); document.write( "\n" ); document.write( "\"C%2861%2C3%29+=+%2861%2A60%2A59%29%2F%283%2A2%2A1%29\" Expand out \"3%21\" to get \"3%2A2%2A1\"\r
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\n" ); document.write( "\n" ); document.write( "At this point, we have three numbers multiplied in the numerator. It is not a coincidence this lines up with r = 3. So another shortcut is to start with the number n = 61 and count down by 1 until you have r = 3 items to multiply out in the numerator. Then you divide over 3! = 3*2*1\r
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\n" ); document.write( "\n" ); document.write( "Let's simplify\r
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\n" ); document.write( "\n" ); document.write( "\"C%2861%2C3%29+=+%2861%2A60%2A59%29%2F%283%2A2%2A1%29\" \r
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\n" ); document.write( "\n" ); document.write( "\"C%2861%2C3%29+=+215940%2F6\" \r
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\n" ); document.write( "\n" ); document.write( "\"C%2861%2C3%29+=+35990\" \r
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\n" ); document.write( "\n" ); document.write( "There are 35990 ways to pick the Democrats.\r
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\n" ); document.write( "\n" ); document.write( "We'll use this number later, so let A = 35990\r
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\n" ); document.write( "\n" ); document.write( "Repeat for the Republicans\r
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\n" ); document.write( "\n" ); document.write( "n = 39\r
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\n" ); document.write( "\n" ); document.write( "r = 3\r
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\n" ); document.write( "\n" ); document.write( "\"C%28n%2C+r%29+=+%28n%21%29%2F%28+r%21%2A%28n-r%29%21+%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"C%2839%2C+3%29+=+%2839%21%29%2F%28+3%21%2A%2839-3%29%21+%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"C%2839%2C+3%29+=+%2839%21%29%2F%28+3%21%2A36%21+%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"C%2839%2C+3%29+=+%2839%2A38%2A37%2A36%21%29%2F%28+3%21%2A36%21+%29\" Use the factorial trick\r
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\n" ); document.write( "\n" ); document.write( " Terms pair up\r
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\n" ); document.write( "\n" ); document.write( "\"C%2839%2C+3%29+=+%2839%2A38%2A37%2Across%2836%21%29%29%2F%28+3%21%2Across%2836%21%29+%29\" and cancel out\r
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\n" ); document.write( "\n" ); document.write( "\"C%2839%2C+3%29+=+%2839%2A38%2A37%29%2F%28+3%21+%29\" Since r = 3, we have 3 numbers multiplied in the numerator. We started at n = 39 and counted down by 1 each time.\r
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\n" ); document.write( "\n" ); document.write( "\"C%2839%2C+3%29+=+%2839%2A38%2A37%29%2F%28+3%2A2%2A1+%29\" Expand out \"3%21\" to get \"3%2A2%2A1\"\r
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\n" ); document.write( "\n" ); document.write( "\"C%2839%2C+3%29+=+%28+54834+%29%2F%28+6+%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"C%2839%2C+3%29+=+9139\"\r
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\n" ); document.write( "\n" ); document.write( "Let B = 9139 represent the number of ways to pick the Republicans.\r
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\n" ); document.write( "\n" ); document.write( "To summarize what we found so far,
\n" ); document.write( "A = 35990 is the number of ways to pick the Democrats
\n" ); document.write( "B = 9139 is the number of ways to pick the Republicans\r
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\n" ); document.write( "\n" ); document.write( "So,
\n" ); document.write( "A*B = 35990*9139 = 328,912,610 is the number of ways to pick the entire committee.
\n" ); document.write( "Order does not matter.
\n" ); document.write( "This number is very close to 329 million.
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