document.write( "Question 1152782: hello could you please help me with this problem-thank you \r
\n" ); document.write( "\n" ); document.write( "The circumference of a circle (measured in inches) is 2/3 the area of the circle (measured in square inches). What is the circle's radius?
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Algebra.Com's Answer #774856 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "The circumference of a circle is:\r
\n" ); document.write( "\n" ); document.write( "\"C=2r%2Api\"\r
\n" ); document.write( "\n" ); document.write( " the area of the circle is:\r
\n" ); document.write( "\n" ); document.write( "\"A=r%5E2%2Api\"\r
\n" ); document.write( "\n" ); document.write( "if the circumference of a circle is \"2%2F3\" the area of the circle, we have\r
\n" ); document.write( "\n" ); document.write( "\"C=%282%2F3%29A\".......substitute \"C\" and \"A\"\r
\n" ); document.write( "\n" ); document.write( "\"2r%2Api=%282%2F3%29r%5E2%2Api\"...simplify\r
\n" ); document.write( "\n" ); document.write( "\"2cross%28r%29%2Across%28pi%29=%282%2F3%29r%5Ecross%282%29%2Across%28pi%29\"\r
\n" ); document.write( "\n" ); document.write( "\"2=%282%2F3%29r\"\r
\n" ); document.write( "\n" ); document.write( "\"r=2%2F%282%2F3%29\"\r
\n" ); document.write( "\n" ); document.write( "\"r=6%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"r=3\"\r
\n" ); document.write( "\n" ); document.write( "check:\r
\n" ); document.write( "\n" ); document.write( "\"C=2r%2Api\"=>\"C=2%2A3%2Api\"=>\"C=6%2Api\"\r
\n" ); document.write( "\n" ); document.write( "\"A=r%5E2%2Api\"=>\"A=3%5E2%2Api\"=>\"A=9%2Api\"\r
\n" ); document.write( "\n" ); document.write( "\"C=%282%2F3%29A\"=>\"C=%282%2F3%299pi=%2818%2F3%29pi=6pi\"\r
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