document.write( "Question 1152778: The value of Sara's new car decreases at a rate of 8% each year.\r
\n" ); document.write( "\n" ); document.write( "Write an exponential function to model the decrease in the car's value each month.
\n" ); document.write( "Write an exponential function to model the decrease in the car's value each week.
\n" ); document.write( "Write an exponential function to model the decrease in the car's value each day.
\n" ); document.write( "What relationship is there between the amount of decrease and the time interval measured?
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Algebra.Com's Answer #774853 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "The formula for the amount of decrease in the car is
\n" ); document.write( "\"y=%28r%2Fn%29\", where \"r\" is the percent (written as a decimal) of decrease per year and\"+n\" is the number of time periods per year.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-For months, there are \"12\" months per year, so \"n+=+12\". \r
\n" ); document.write( "\n" ); document.write( "The rate is \"8\"%;= \"8%2F100+=+0.08\". \r
\n" ); document.write( "\n" ); document.write( "This gives us
\n" ); document.write( "\"+y=%280.08%2F12%29\". Dividing, we get
\n" ); document.write( "\"y=%280.0067%29\"\r
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\n" ); document.write( "\n" ); document.write( "-For weeks, there are \"52\" weeks per year, so \"n+=+52\".
\n" ); document.write( "The rate is still \"0.08\"; this gives us
\n" ); document.write( "\"y=%280.08%2F52%29\"
\n" ); document.write( "\"y=%280.0015%29\"\r
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\n" ); document.write( "\n" ); document.write( "-For days, there are \"365.25\" days per year, so\"+n+=+365.25\".
\n" ); document.write( "The rate is still \"0.08\"; this gives us
\n" ); document.write( "\"y=%280.08%2F365.25%29\"
\n" ); document.write( "\"+y=%280.0002%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-Comparing the number of weeks to the number of months, \"52%2F12+=+4.3\".
\n" ); document.write( "There are \"4.3\" times more weeks in a year than there are days.
\n" ); document.write( "The amount of decrease from months to weeks went from
\n" ); document.write( "\"0.0067%CB%A3+to+0.0015\"
\n" ); document.write( "\"+0.0015%2F0.0067+=+0.2234\", which is close to \"1%2F4.3\".\r
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\n" ); document.write( "\n" ); document.write( "-Comparing the number of days to the number of weeks, \r
\n" ); document.write( "\n" ); document.write( "\"365.25%2F52+=+7.02\". \r
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\n" ); document.write( "\n" ); document.write( "There are \"7.02\" times more days in a year than there are weeks. \r
\n" ); document.write( "\n" ); document.write( "The amount of decrease from weeks to days went from \r
\n" ); document.write( "\n" ); document.write( "\"0.0002%2F0.0015+=+0.1333\", which is close to \"1%2F7.02\".\r
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\n" ); document.write( "\n" ); document.write( "answers:\r
\n" ); document.write( "\n" ); document.write( "1) \"y=%280.08%2F12%29=+0.0067\"-For months\r
\n" ); document.write( "\n" ); document.write( "2) \"y=%280.08%2F52%29=+0.0015\"-For weeks\r
\n" ); document.write( "\n" ); document.write( "3) \"y=%280.08%2F365.25%29+=+0.0002\"-For days\r
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