document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1152747>Question 1152747</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man has a collection of dimes and quarters with a total of $3.50. If he has 7 more dimes than quarters, how many of each coins does he have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #774840 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=774840\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A man has a collection of dimes and quarters with a total of $3.50. If he has 7 more dimes than quarters, how many of each coins does he have?<BR>\n" );
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document.write( "Set the \"7 more dimes\" aside.<BR>\n" );
document.write( "Now it's pairs of 1Q & 1D worth $2.80<BR>\n" );
document.write( "280/35 = 8 pairs.<BR>\n" );
document.write( "+ 7 dimes ---> 8Q & 15D<BR>\n" );
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