document.write( "Question 1152747: A man has a collection of dimes and quarters with a total of $3.50. If he has 7 more dimes than quarters, how many of each coins does he have? \n" ); document.write( "

Algebra.Com's Answer #774832 by math_helper(2461) $\"\"$ $\"About$

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document.write( "q = number of quarters
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document.write( "d = number of dimes = q+7\r
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document.write( "25q + 10(q+7) = 350   (cents)
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document.write( "35q + 70 = 350
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document.write( "35q = 280
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document.write( "q = 280/35 = 8  --->  d = 15\r
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document.write( "Ans: 8 quarters and 15 dimes
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document.write( "Check:
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document.write( " 25(8) + 10(15) = 200 + 150 = 350  (= $3.50) (ok) \n" );
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