document.write( "Question 1152726: If 0° < A, B < 90°, and sinA = cosB, compute cot(A+B) \n" ); document.write( "
Algebra.Com's Answer #774811 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\"sin%28A%29+=+cos%28B%29\" if and only if \"A%2BB+=+90\". We say that angles A and B are complementary\r
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\n" ); document.write( "\n" ); document.write( "For example, \"sin%2840%29+=+cos%2850%29\" because \"40%2B50+=+90\"
\n" ); document.write( "Using a calculator, \"sin%2840%29+=+0.6427876\" and \"cos%2850%29+=+0.6427876\" (both approximate).\r
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\n" ); document.write( "\n" ); document.write( "Because we are working with cotangent, let's start with the identity for tangent and rewrite it in terms of cotangent.\r
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\n" ); document.write( "\n" ); document.write( "\"tan%28x%29+=+sin%28x%29%2Fcos%28x%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"tan%28x%29%2F1+=+sin%28x%29%2Fcos%28x%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"1%2Ftan%28x%29+=+cos%28x%29%2Fsin%28x%29\" Apply reciprocal to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"cot%28x%29+=+cos%28x%29%2Fsin%28x%29\" We will use this later. Call this equation (1).\r
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\n" ); document.write( "\n" ); document.write( "It might be tempting to use the reciprocal identity \"cot%28x%29+=+1%2F%28tan%28x%29%29\" but if \"x+=+90\" degrees, then \"tan%28x%29+=+0\", making \"1%2F%28tan%28x%29%29\" to be undefined. Instead it is better to use \"cot%28x%29+=+cos%28x%29%2Fsin%28x%29\"\r
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\n" ); document.write( "\n" ); document.write( "With that in mind, we can compute the cotangent value.\r
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\n" ); document.write( "\n" ); document.write( "\"cot%28A%2BB%29+=+cot%2890%29\" Replace A+B with 90.\r
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\n" ); document.write( "\n" ); document.write( "\"cot%28A%2BB%29+=+cos%2890%29%2Fsin%2890%29\" Use equation (1).\r
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\n" ); document.write( "\n" ); document.write( "\"cot%28A%2BB%29+=+0%2F1\" Use the unit circle to compute cos(90) and sin(90).\r
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\n" ); document.write( "\n" ); document.write( "\"cot%28A%2BB%29+=+0\" Final answer.
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