document.write( "Question 1152706: An astronaut on the moon throws a baseball upward. The astronaut is 6​ ft, 6 in.​ tall, and the initial velocity of the ball is 30 ft per sec. The height s of the ball in feet is given by the equation s equals -2.7t^2 + 30t + 6.5​, where t is the number of seconds after the ball was thrown. Complete parts a and b.
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Algebra.Com's Answer #774788 by Alan3354(69443)\"\" \"About 
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s equals -2.7t^2 + 30t + 6.5​, where t is the number of seconds after the ball was thrown. Complete parts a and b.
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\n" ); document.write( "a. After how many seconds is the ball 12 ft above the​ moon's surface?
\n" ); document.write( "s(t) = -2.7t^2 + 30t + 6.5 = 12
\n" ); document.write( "2.7t^2 - 30t + 5.5 = 0
\n" ); document.write( "Solve for t
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\n" ); document.write( "The smaller value is ascending.
\n" ); document.write( "The larger is descending.
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