document.write( "Question 1152686: Two lines L1 and L2 intersect at point P.L1 passes through points(-4,0)and(0,6).
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document.write( "Given that L2 has the equation:y=2x-2,find by calculation the coordinates of P. \n" );
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Algebra.Com's Answer #774757 by Theo(13342)![]() ![]() You can put this solution on YOUR website! line 1 passes through the points (-4,0) and (0,6) \n" ); document.write( "let y1 = (-4,0) and let y2 = (0,6) \n" ); document.write( "the slope of line 1 is (y2 - y1) / (x2 - x1) = 6/4 = 1.5. \n" ); document.write( "the slope intercept format of a straight line is y = mx + b \n" ); document.write( "m = the slope \n" ); document.write( "b equal the y-intercept. \n" ); document.write( "the y-intercept of line 1 is the value of y when x = 0. \n" ); document.write( "that makes the y-intercept of line 1 equal to 6. \n" ); document.write( "the equation of line 1 is therefore y = 1.5 * x + 6 \n" ); document.write( "the equation of line 2 is y = 2 * x - 2. \n" ); document.write( "the two lines intersect when 1.5 * x + 6 = 2 * x - 2 \n" ); document.write( "subtract 1.5 * x from both sides of that equation and add 2 to both sides of that equation to get: \n" ); document.write( "8 = .5 * x \n" ); document.write( "solve for x to get: \n" ); document.write( "x = 8 / .5 = 16 \n" ); document.write( "when x = 16, y = 1.5 * x + 6 becomes 30 \n" ); document.write( "when x = 16, y = 2 * x - 2 becomes 30 \n" ); document.write( "the point (16,30) is a common point to both lines and is therefore the intersection of those two lines. \n" ); document.write( "here's what the graph of both those equations looks like. \n" ); document.write( "it can be seen that the intersection of the two lines is at the point (16,30).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( " |