document.write( "Question 1152676: Square steel rods weigh 1/3 lb. / linear foot and are 5/16 in. on each side. Calculate total length of a group that weighs 23 3/4 lbs.\r
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\n" ); document.write( "\n" ); document.write( "My attempt:\r
\n" ); document.write( "\n" ); document.write( "23.75 / .33333 = 71.25 ft.\r
\n" ); document.write( "\n" ); document.write( "Not sure if my calculations are correct.
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Algebra.Com's Answer #774743 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "You have the correct answer. It is equivalent to 71 & 1/4 feet (see Note 2 below). Nice work.\r
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\n" ); document.write( "\n" ); document.write( "Here is another way to get the answer.\r
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\n" ); document.write( "\n" ); document.write( "The info that the square rods are \"5/16 in. on each side\" is never used.
\n" ); document.write( "We only use the information that they weigh 1/3 lb. per linear foot and that the total weight is 23 & 3/4 pounds.\r
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\n" ); document.write( "\n" ); document.write( "23 & 3/4 pounds = 23.75 pounds\r
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\n" ); document.write( "\n" ); document.write( "1/3 lb. per linear foot
\n" ); document.write( "1/3 lb : 1 foot
\n" ); document.write( "1 lb : 3 feet ......... multiply both parts of the ratio by 3 (see Note 1 below)
\n" ); document.write( "23.75*1 lb : 23.75*3 feet ......... multiply both parts by 23.75
\n" ); document.write( "23.75 lb : 71.25 feet\r
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\n" ); document.write( "\n" ); document.write( "71.25 feet = 71 & 1/4 feet\r
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\n" ); document.write( "\n" ); document.write( "71.25 feet of rods weigh 23.75 pounds
\n" ); document.write( "71 & 1/4 feet of rods weigh 23 & 3/4 pounds (see Note 2 below)\r
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\n" ); document.write( "\n" ); document.write( "Footnotes:
  • Note 1: multiplying both sides of an equation by 3 is the same as dividing both sides by 1/3 = 0.33333333... (the dots indicating the '3's go on forever) Example: 1/5 divided by 1/3 = 1/5 times 3/1 = 1/5 times 3. So this is why we are getting the same answer despite taking slightly different paths.
  • Note 2: Your teacher did not state how the final answer format should be; however, I'm assuming that the teacher wants a mixed number since none of the given values are in decimal format. Though of course it's best to ask the teacher directly to clear up any confusion.

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