document.write( "Question 1152392: In a Gallup poll, 2400 randomly selected adults were surveyed and 39% of them said that they used the internet for shopping at least a few times a year. Find a 95% confidence interval estimate of the percentage of adults who use the internet for shopping. \n" ); document.write( "
Algebra.Com's Answer #774716 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! 95% half-interval is 1.96*sqrt(p*(1-p)/n) \n" ); document.write( "this is 1.96*sqrt (.39*.61/2400) \n" ); document.write( "=0.0195 \n" ); document.write( "so the interval is (0.3705, 0.4095) \n" ); document.write( " |