document.write( "Question 1152654: hello tutors: (2logx)=x over 25. im not sure how to go about this log equation.do i cross multiply.change 25 to 5^2..really not sure...Can i have a step by step explanation. Thank you tutors for all your great help. \n" ); document.write( "
Algebra.Com's Answer #774694 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"2log%28x%29=x%2F25\"\r
\n" ); document.write( "\n" ); document.write( "\"2%2A25log%28x%29=x\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28x%29=x%2F50\"....................if \"f+%28x+%29=g+%28x+%29\", then \"a%5E%28f+%28x+%29%29=a%5E%28g%28x%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"10%5E%28log%2810%2Cx%29%29=10%5E%28x%2F50%29\".......simplify : \"10%5E%28log%2810%2Cx%29%29=+x\"\r
\n" ); document.write( "\n" ); document.write( "\"x=10%5E%28x%2F50%29\"...............use Lambert form: \"xe%5E%28-+ln+%2810+%29x%2F50%29%29=1\"\r
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\n" ); document.write( "\n" ); document.write( "rewrite the equation with :\"+u=-%28ln+%2810+%29x%29%2F50\" and \"x=+-50u%2Fln+%2810%29\"\r
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\n" ); document.write( "\"%28-+50u%2Fln+%2810%29%29e%5Eu=1\"=> in Lambert form is \"e%5Eu%2Au=-%28ln%2810%29%2F50%29\"\r
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\n" ); document.write( "\n" ); document.write( "solve \"e%5Eu%2Au=-ln%2810%29%2F50%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"u=-2ln%2810%29\", \"u=+W%5B0%5D%28-ln%2810%29%2F50%29\"\r
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\n" ); document.write( "\n" ); document.write( "substitute back :\"u=-%28ln%2810%29x%29%2F50%29\", solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"-%28ln+%2810+%29x%29%2F50=-2%2Aln%2810%29\"\r
\n" ); document.write( "\n" ); document.write( "\"-%28ln+%2810+%29%29x=-2%2A50%2Aln%2810%29\"\r
\n" ); document.write( "\n" ); document.write( "\"-ln+%2810+%29x=-100%2Aln%2810%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x=%28-100%2Aln%2810%29%29%2F%28-ln+%2810%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x=100\"\r
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\n" ); document.write( "\n" ); document.write( "solve \"-%28ln+%2810+%29%29x%2F50=+W%5B0%5D%28-ln%2810%29%2F50%29\"\r
\n" ); document.write( "\n" ); document.write( "\"-%28ln+%2810+%29%29x=50W%5B0%5D%28%28-ln%2810%29%29%2F50%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=50W%5B0%5D%28%28-ln%2810%29%29%2F50%29%2F%28-%28ln+%2810+%29%29%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=-%2850W%5B0%5D%28-ln%2810%29%2F50%29%29%2Fln+%2810%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=-%2850W%5B0%5D%28-1%2F50%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=50W%5B0%5D%2F50\"\r
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\n" ); document.write( "\n" ); document.write( "The solutions are:\r
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\n" ); document.write( "\n" ); document.write( "\"x=100\", \"x=50W%5B0%5D%2F50\"\r
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