document.write( "Question 106453: Hi, I can't figure out this problem, could you help?\r
\n" ); document.write( "\n" ); document.write( "\"+a%2F%28b%2B%28c%2Fd%29%29=c+\"\r
\n" ); document.write( "\n" ); document.write( "How do you solve for c? thanks.
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Algebra.Com's Answer #77464 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
First thing is to get all of the terms containing 'c' on one side of the equation:\r
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\n" ); document.write( "\n" ); document.write( "\"+a%2F%28b%2B%28c%2Fd%29%29=c+\"\r
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\n" ); document.write( "\n" ); document.write( "\"a=c%28b%2B%28c%2Fd%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now if we multiply both sides by 'd', we can get rid of that pesky denominator on the right.\r
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\n" ); document.write( "\n" ); document.write( "\"ad=c%28bd%2Bc%29\"\r
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\n" ); document.write( "\n" ); document.write( "Distribute 'c'\r
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\n" ); document.write( "\n" ); document.write( "\"ad+=+bdc+%2B+c%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "And rearrange to standard quadratic form:\r
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\n" ); document.write( "\n" ); document.write( "\"c%5E2+%2B+bdc+-ad+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "now solve for 'c' using the quadratic formula:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"\r
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\n" ); document.write( "\n" ); document.write( "except that you would substitute 'c' for 'x'; 'bd' for 'b'; 1 for a; and 'ad' for 'c', thus:\r
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\n" ); document.write( "\n" ); document.write( "\"c+=+%28-bd+%2B-+sqrt%28+%28bd%29%5E2-4%2Aad+%29%29%2F%282%29+\"\r
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\n" ); document.write( "\n" ); document.write( "General hint: The variable for which you were solving existed in the numerator on one side of the equation, and in the denominator on the other side. That guaranteed that you were going to be dealing with a quadratic.
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