document.write( "Question 1152544: A woman invested 4 times as much at 3% as she did at 6%. The total amount of interest she earns in 1 year from both accounts is $1,620. How much did she invest at each rate? \n" ); document.write( "

Algebra.Com's Answer #774622 by greenestamps(13200) $\"\"$ $\"About$

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\n" ); document.write( "Here is an unorthodox way of solving the problem that works for me....

\n" ); document.write( "(1) Determine the average interest rate, given that 4 times as much was invested at 3% as at 6%:

\n" ); document.write( " $\"%284%28.03%29%2B1%28.06%29%29%2F5+=+0.036\"$

\n" ); document.write( "(2) Determine the total amount invested, given the interest of $1620 and knowing the average interest rate:

\n" ); document.write( " $\"0.036%28x%29+=+1620\"$
\n" ); document.write( " $\"x+=+1620%2F0.036+=+45000\"$

\n" ); document.write( "(3) Divide the total of $45,000 in the ratio 4:1

\n" ); document.write( "ANSWER: $36,000 at 3%; $9000 at 6%

\n" ); document.write( "CHECK: .03(36000)+.06(9000) = 1080+540 = 1620

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