document.write( "Question 1152431: Suppose certain coins have weights that are normally distributed with a mean of 5.078 g and a standard deviation of 0.072 g. A vending machine is configured to accept those coins with weights between 4.948 g and 5.208 g.
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document.write( "a. If 270 different coins are inserted into the vending​ machine, what is the expected number of rejected​ coins?
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document.write( "The expected number of rejected coins is \n" );
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Algebra.Com's Answer #774603 by VFBundy(438)![]() ![]() You can put this solution on YOUR website! Probability coin is less than 4.948 grams: \n" ); document.write( " \n" ); document.write( "z-score = \n" ); document.write( " \n" ); document.write( "Look up -1.81 on a z-table. You get an answer of 0.0351. This is the probability the a coin is less than 4.948 grams. \n" ); document.write( " \n" ); document.write( "Probability coin is more than 5.208 grams: \n" ); document.write( " \n" ); document.write( "z-score = \n" ); document.write( " \n" ); document.write( "Look up 1.81 on a z-table. You get an answer of 0.9649. This is the probability a coin is LESS than 5.208 grams. We want to find the probability a coin is MORE than 5.208 grams. So, if the probability a coin is less than 5.208 grams is 0.9649, the probability it is more than 5.208 grams is 0.0351. \n" ); document.write( " \n" ); document.write( "So, the probability the coin does NOT fall in the accepted range is 0.0351 + 0.0351...or 0.0702. \n" ); document.write( " \n" ); document.write( "Because there are 270 coins, and the probability a coin will be rejected is 0.0702, the number of expected rejected coins is: \n" ); document.write( " \n" ); document.write( "270 * 0.0702 = 18.954...or, rounded off, 19. |