document.write( "Question 1152544: A woman invested 4 times as much at 3% as she did at 6%. The total amount of interest she earns in 1 year from both accounts is $1,620. How much did she invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #774596 by VFBundy(438)![]() ![]() You can put this solution on YOUR website! 3% account: \n" ); document.write( "Principal = 4p \n" ); document.write( "Rate = 0.03 \n" ); document.write( "Interest = 4p * 0.03 = 0.12p \n" ); document.write( " \n" ); document.write( "6% account: \n" ); document.write( "Principal = p \n" ); document.write( "Rate = 0.06 \n" ); document.write( "Interest = p * 0.06 = 0.06p \n" ); document.write( " \n" ); document.write( "0.12p + 0.06p = 1620 \n" ); document.write( " \n" ); document.write( "0.18p = 1620 \n" ); document.write( " \n" ); document.write( "p = 9000 \n" ); document.write( " \n" ); document.write( "3% account: \n" ); document.write( "Principal = 4p = $36,000 \n" ); document.write( " \n" ); document.write( "6% account: \n" ); document.write( "Principal = p = $9000 |