document.write( "Question 1152544: A woman invested 4 times as much at 3% as she did at 6%. The total amount of interest she earns in 1 year from both accounts is $1,620. How much did she invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #774596 by VFBundy(438)\"\" \"About 
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3% account:
\n" ); document.write( "Principal = 4p
\n" ); document.write( "Rate = 0.03
\n" ); document.write( "Interest = 4p * 0.03 = 0.12p
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\n" ); document.write( "6% account:
\n" ); document.write( "Principal = p
\n" ); document.write( "Rate = 0.06
\n" ); document.write( "Interest = p * 0.06 = 0.06p
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\n" ); document.write( "0.12p + 0.06p = 1620
\n" ); document.write( "
\n" ); document.write( "0.18p = 1620
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\n" ); document.write( "p = 9000
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\n" ); document.write( "3% account:
\n" ); document.write( "Principal = 4p = $36,000
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\n" ); document.write( "6% account:
\n" ); document.write( "Principal = p = $9000
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