document.write( "Question 106443: Red candle: 45 cm tall and burns 3cm per hour
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document.write( "White candle: 30 cm tall and burns 1 1/2 cm per hour.\r
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document.write( "How tall will each candle be after 1 hour?\r
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document.write( "How tall will each candle be after 3 hours?\r
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document.write( "How tall will each candle be after 12 hours?\r
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document.write( "Can you generalize-a formula- a system for calculating the candle's height at any given time?\r
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document.write( "Which candle will last longer? How do you know?\r
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document.write( "If you burn both candles continously (same start time) will they ever be the same height at the same time? \n" );
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Algebra.Com's Answer #77456 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Red candle: 45 cm tall and burns 3cm per hour \n" ); document.write( "White candle: 30 cm tall and burns 1 1/2 cm per hour. \n" ); document.write( ": \n" ); document.write( "How tall will each candle be after 1 hour? \n" ); document.write( "Red: 45 - (1*3) = 42 cm \n" ); document.write( "White: 30 - (1*1.5) = 28.5 cm \n" ); document.write( ": \n" ); document.write( "How tall will each candle be after 3 hours? \n" ); document.write( "Red: 45 - (3*3) = 36 cm \n" ); document.write( "White: 30 - (3*1.5) = 25.5 cm \n" ); document.write( ": \n" ); document.write( "How tall will each candle be after 12 hours? \n" ); document.write( "Red: 45 - (12*3) = 9 cm \n" ); document.write( "White: 30 - (12*1.5) = 12 cm \n" ); document.write( ": \n" ); document.write( "Can you generalize-a formula- a system for calculating the candle's height at any given time? \n" ); document.write( "Let t = time in hrs and h = height in cm \n" ); document.write( "Red: h = 45 - 3t \n" ); document.write( "White: h = 30 - 1.5t \n" ); document.write( ": \n" ); document.write( "Which candle will last longer? How do you know? \n" ); document.write( "The white one. The red burns twice as fast, but it is less than twice as tall \n" ); document.write( ": \n" ); document.write( "If you burn both candles continuously (same start time) will they ever be the same height at the same time? \n" ); document.write( ": \n" ); document.write( "Use the equations to see how long (t), they will be the same height \n" ); document.write( "30 - 1.5t = 45 - 3t \n" ); document.write( "+3t - 1.5t = 45 - 30 \n" ); document.write( "1.5t = 15 \n" ); document.write( "t = 15/1.5 \n" ); document.write( "t = 10 hrs they will be the same \n" ); document.write( ": \n" ); document.write( "Check the height when they are the same: \n" ); document.write( "45 - (3*10) = 15\" \n" ); document.write( "30 - (1.5*10) = 15\" \n" ); document.write( " \n" ); document.write( " |