document.write( "Question 1152486: The weight of a small Starbucks coffee is a normally distributed random variable with a mean of 395 grams and a standard deviation of 22 grams. Find the weight that corresponds to each event. (Use Excel or Appendix C to calculate the z-value. Round your final answers to 2 decimal places.)
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document.write( "a. Highest 30 percent
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document.write( "b. Middle 70 percent to (2 answers)\r
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document.write( "c. Highest 90 percent
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document.write( "d. Lowest 20 percent
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Algebra.Com's Answer #774505 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! For 70th percentile or highest 30 per cent z=0.52 \n" ); document.write( "z=(x-mean)/sd \n" ); document.write( "0.5244=(x-395)/22 \n" ); document.write( "11.54=x-395 \n" ); document.write( "x=406.54 gm \r \n" ); document.write( "\n" ); document.write( "middle 70% is from 15 to 85 per cent. Use symmetry and figure 1 \n" ); document.write( "z.15 is -1.036 \n" ); document.write( "-22.80=x-395 \n" ); document.write( "x=372.20 gm \n" ); document.write( "the other value, the 85th percentile, is 395+22.80=417.80 gm. That is range.\r \n" ); document.write( "\n" ); document.write( "highest 90% is z=1.282 \n" ); document.write( "28.20=(x-mean) \n" ); document.write( "x=423.20\r \n" ); document.write( "\n" ); document.write( "Lowest 20% is -0.8416=z \n" ); document.write( "-18.52=x-395 \n" ); document.write( "x=376.48 gm\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |