document.write( "Question 106434This question is from textbook Mechanics I
\n" );
document.write( ": Hey again! :D
\n" );
document.write( "A particle has position 2i + j initially and is moving with speed 10ms-1 in the direction 3i - 4j. Find it's position vector when t = 3 and the distance it has travelled in those 3 seconds.
\n" );
document.write( "I know the distance travelled is Speed * time, so 10 * 3 = 30metres. \r
\n" );
document.write( "\n" );
document.write( "I have already posted this topic, because the people gave the correct answers, ( thanks alot to you all for helping! :P )\r
\n" );
document.write( "\n" );
document.write( "but i still dont understand how you got them, i thought, if in 1 second, you do 3i - 4j\r
\n" );
document.write( "\n" );
document.write( "then in 3 seconds you do, 9i - 12j, add on the original, so 11i - 11j, \r
\n" );
document.write( "\n" );
document.write( "i have no idea how you got to 20i and 23j, i can see with 3i-4j, if you multiply everythign by 6, you get a figure that once added to the original 2i + j, gives the answer, but again why 6? :( Thanks again in advanced \n" );
document.write( "
Algebra.Com's Answer #77446 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! You start at (2,1) \n" ); document.write( "In one second you move 10 meters or directionally (6,-8) since \n" ); document.write( " \n" ); document.write( "6,8,10 are the Pythagorean triple (3,4,5)x2. \n" ); document.write( "So in one second you are at (using ordered pair(vector) addition), \n" ); document.write( "(2,1)+(6,-8)=(8,-7) \n" ); document.write( "After another second you move another (6,-8) \n" ); document.write( "(8,-7)+(6,-8)=(14,-15) \n" ); document.write( "and after the third second, you move another (6,-8) \n" ); document.write( "(14,15)+(6,-8)=(20,-23) \n" ); document.write( "If you went on another second, you would move to \n" ); document.write( "(20,-23)+(6,-8)=(26,-31) \n" ); document.write( "and so on. \n" ); document.write( " \n" ); document.write( " |