document.write( "Question 1152425: Frank bought 2 shirts and 1 pair of dress pants for a total of $55. If he had bought 1 shirt and 2 pairs of dress pants, he would have paid $68. What was the price of each shirt and each pair of dress pants? \n" ); document.write( "
Algebra.Com's Answer #774457 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Translating the given information directly into equations gives us \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "While solving that pair of equations using substitution, as the other tutor did, is valid, there are other ways that are far less work. \n" ); document.write( "The solution with formal algebra using substitution is hard to interpret in everyday language; there are at least a couple of ways to solve the pair of equations using formal algebra for which it is easy to see how common sense makes the solution processes easy to understand. \n" ); document.write( "Here are a couple of solutions that use algebra that is easily described in everyday language. \n" ); document.write( "(1) One standard method for solving pairs of linear equations -- and the most straightforward when the information is given in this way -- is elimination: multiply one or both equations by some constant so that you can use the two resulting equations to eliminate one variable by either adding or subtracting the two equations. \n" ); document.write( "In common sense language, suppose that, instead of buying 1 shirt and 2 pairs of pants for $68, he bought 2 shirts and 4 pairs of pants. That would cost him $136. Algebraically, \"multiply the second equation by 2\": \n" ); document.write( " \n" ); document.write( "Now compare the two purchases (subtract the first equation from this new equation): \n" ); document.write( " \n" ); document.write( "In everyday language, the difference between the two purchases is now 3 extra pairs of pants, for an extra $81; that means each pair of pants costs $81/3 = $27. \n" ); document.write( "Then use that fact with any of the purchases to determine the cost of each shirt. \n" ); document.write( "(2) And here is a method that uses an unusual algebraic approach but is very understandable with common sense. \n" ); document.write( "Between the two purchases described in the problem, the difference is one more pair of pants and one less shirt, for an increase of $13 in the total cost. (Algebraically, to find the difference between the two purchases, subtract the first equation from the second): \n" ); document.write( " \n" ); document.write( "So let's make a third purchase where we again add one pair of pants and subtract one shirt. That gives us three pairs of pants and no shirts, for a cost of $68+$13 = $81. \n" ); document.write( "So again we find the cost of each pair of pants to be $81/3 = $27. \n" ); document.write( " |