document.write( "Question 1152387: Hi! I had this interval: \"+1.99%3C1%2Fx%3C2.01+\". When I took the reciprocal of each number, I ended up with: \"+1%2F1.99%3Cx%3C1%2F2.01+\". However, this leaves me with the larger number on the left side and the smaller number on the right side. This wouldn't make sense. What did I do wrong? Can I rearrange the numbers?
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Algebra.Com's Answer #774398 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
Hi! I had this interval: \"+1.99%3C1%2Fx%3C2.01+\". When I took the reciprocal of each number, I ended up with: \"+1%2F1.99%3Cx%3C1%2F2.01+\". However, this leaves me with the larger number on the left side and the smaller number on the right side. This wouldn't make sense. What did I do wrong? Can I rearrange the numbers?
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\n" ); document.write( "Inversion changes the polarity for inequalities.
\n" ); document.write( "eg,
\n" ); document.write( "if 1/x < 1/3, then x > 3
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\n" ); document.write( "\"+1.99%3C1%2Fx%3C2.01+\"
\n" ); document.write( "\"+1%2F1.99+%3E+x+%3E+1%2F2.01+\"
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