document.write( "Question 1152387: Hi! I had this interval: \"+1.99%3C1%2Fx%3C2.01+\". When I took the reciprocal of each number, I ended up with: \"+1%2F1.99%3Cx%3C1%2F2.01+\". However, this leaves me with the larger number on the left side and the smaller number on the right side. This wouldn't make sense. What did I do wrong? Can I rearrange the numbers?
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Algebra.Com's Answer #774397 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"+1.99%3C1%2Fx%3C2.01+\"......took the reciprocal of each number, they will switch sides\r
\n" ); document.write( "\n" ); document.write( "\"+1%2F1.99+%3Cx%3C+1%2F2.01\"\r
\n" ); document.write( "\n" ); document.write( "\"0.503%3C+x+%3C++0.479+++\"->false; \"no\" \"solution\"\r
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\n" ); document.write( "\n" ); document.write( "If \"a%3Cu%3Cb\" then \"a%3Cu\" and \"u%3Cb\".\r
\n" ); document.write( "\n" ); document.write( "you have\r
\n" ); document.write( "\n" ); document.write( "\"+1%2F1.99+%3Cx\" and \"x%3C+1%2F2.01\"\r
\n" ); document.write( "\n" ); document.write( "then, you switch sides to get true statement:\r
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\n" ); document.write( "\n" ); document.write( "\"+1%2F2.01%3Cx%3C+1%2F1.99+\"\r
\n" ); document.write( "\n" ); document.write( "\"0.479%3C+x+%3C+0.503++++\"\r
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