document.write( "Question 1152304: Find some value R, \"R%21%2F%28%28R-3%29%21%28R-4%29%21%29=1\". Find the sum of the digits of R.\r
\n" ); document.write( "\n" ); document.write( "R! over (R-3)!(R-4)! = 1
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Algebra.Com's Answer #774301 by math_helper(2461)\"\" \"About 
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R!/((R-3)!(R-4)!) = 1\r
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\n" ); document.write( "\n" ); document.write( "Using trial and error...
\n" ); document.write( "8!/(5!*4!) = 8*7*6/(4!) = 336/24 > 1
\n" ); document.write( "9!/(6!*5!) = 9*8*7/(5!) = 504/120 > 1
\n" ); document.write( "10!/(7!*6!) = 10*9*8/(6!) = 720 / 720 = 1\r
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\n" ); document.write( "\n" ); document.write( "So R = 10 satisifies the equation.
\n" ); document.write( "The sum of the digits of R is equal to \"+highlight%28+1+%29+\" \r
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