document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1152278>Question 1152278</A>: <I><SPAN STYLE=\"word-break: break-all;\"> O.k so I have this rational function f(x)=x^2-x-2/4x+8, I am having trouble finding the oblique asymptote. When I perform long division a began by factoring the denominator in the form 4(x+2) because I believe it needs to be in the form x-c. I then carry out the division like normal I end up with a quotient of x-3 with a remainder of 4. My question is what happens with the 4 that I factored in the divisor? When I check the equation for the slant asymptote in my calculator it does not match up. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #774259 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=774259\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You take that x-3 and divide it by the 4 you factored out earlier.  That gives you the right asymptote.  It is messier, but you can also divide 4x+8 into the function and deal with fractions. You will get a slant asymptote of y=(1/4)x-(3/4), which is the same thing.\r<BR>\n" );
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