document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1152270>Question 1152270</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bag contains 15 black balls, 8 green balls and 10 white balls. If the three balls are drawn <BR>\n" );
document.write( "a: with replacement<BR>\n" );
document.write( "b: without replacement<BR>\n" );
document.write( "Find if the balls are:<BR>\n" );
document.write( "i. of the same colour<BR>\n" );
document.write( "ii. of different colour<BR>\n" );
document.write( "iii.two are black one green<BR>\n" );
document.write( "iv.two are white one is black<BR>\n" );
document.write( "v. two are green one is black<BR>\n" );
document.write( "vi. non are black<BR>\n" );
document.write( "vii. non are green<BR>\n" );
document.write( "viii. non are green </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #774257 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=774257\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> With replacement and 33 balls total<BR>\n" );
document.write( "1. Same color (15/33)^3+(8/33)^3+(10/33)^3<BR>\n" );
document.write( "2. different color 1- answer above.<BR>\n" );
document.write( "3. two black and one green- 3 ways to happen so 3*(15/33)(15/33)*8/33<BR>\n" );
document.write( "4. two white and one black- 3(10/33)(10/33)(15/33)<BR>\n" );
document.write( "5. this would be 3*(8/33)(8/33)(15/33)<BR>\n" );
document.write( "6. none is black (18/33)(18/33)*18/33)<BR>\n" );
document.write( "7. none is green (25/33)^3\r<BR>\n" );
document.write( "\n" );
document.write( "with replacement<BR>\n" );
document.write( "1. (15/33)(14/32)(13/31)+(8/33)*(7/32)(6/31)+(10/33)(9/32)(8/31)--here, the numerator decreases by 1 and the denominator as well after each draw.<BR>\n" );
document.write( "2.1- the above answer for different color.<BR>\n" );
document.write( "3. 2 black 1 green.  the factors change, but their product does not.<BR>\n" );
document.write( "this is 3(15/33)(14/32)(8/31)   <BR>\n" );
document.write( "4. 2 white and one black is 3(10/33)(9/32)(15/31)<BR>\n" );
document.write( "5. 2 green and one black is 3(8/33)(7/32)(15/31)<BR>\n" );
document.write( "6. none is black (18/33)(17/32)(16/31)<BR>\n" );
document.write( "7. none is green (25/33)(24/32)(23/31) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );