document.write( "Question 1152235: How much of a 20% benzene solution and how much of a 60% benzene solution should be mixed to make 4 gallons of a 40% benzene solution? Show steps and complete answer please! Thanks! \n" ); document.write( "
Algebra.Com's Answer #774221 by josgarithmetic(39618)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "x, the 20% benzene
\n" ); document.write( "y, the 60% benzene\r
\n" ); document.write( "\n" ); document.write( "\"system%2820x%2B60y=40%2A4%2Cx%2By=4%29\"\r
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\n" ); document.write( "\n" ); document.write( "E1:
\n" ); document.write( "\"x%2B3y=2%2A4\"
\n" ); document.write( "\"x%2B3y=8\"\r
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\n" ); document.write( "\n" ); document.write( "System, \"system%28x%2B3y=8%2Cx%2By=4%29\"\r
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\n" ); document.write( "\n" ); document.write( "E1-E2, \"2y=4\"
\n" ); document.write( "\"highlight%28y=2%29\"--------------------------two gallons of each of the benzene starting solutions.\r
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