document.write( "Question 1152213: What is the area of the figure bounded by x = -3, x = 2, y + 4 = (-2/5)(x - 2), and 5y - x - 13 = 0 when graphed on a coordinate plane? \n" ); document.write( "

Algebra.Com's Answer #774186 by MathTherapy(10552) $\"\"$ $\"About$

You can put this solution on YOUR website!

\n" ); document.write( "What is the area of the figure bounded by x = -3, x = 2, y + 4 = (-2/5)(x - 2), and 5y - x - 13 = 0 when graphed on a coordinate plane?
\n" ); document.write( "

When plotted, the graphs of: 
\n" );
document.write( "a)  and x = - 3 intersect at the point (- 3, 2)
\n" );
document.write( "b)  and x = - 3 intersect at the point (- 3, - 2)
\n" );
document.write( "c)  and x = 2 intersect at the point (2, 3)
\n" );
document.write( "d)  and x = 2 intersect at the point (2, - 4)
\n" );
document.write( "These four points form a trapezoid, with a height of 5 (2 - - 3), as seen on the x-axis
\n" );
document.write( "With the trapezoid's shorter base being 4 [from (- 3, 2) to (- 3, - 2)] units, and longer base being 7 [from (2, 3) to (2, - 4)], 
\n" );
document.write( "we then get the trapezoid's area or the area bounded by the four line graphs as:  \n" );
document.write( "

\n" );