document.write( "Question 106286: a bus leaves a station at 1 p.m traveling west at an average rate of 44 mile an hour. one hour later a second bus leaves the same station traveling east at a rate of 48 mile an hour. at what time will the two buses be 274 mile apart \n" ); document.write( "

Algebra.Com's Answer #77418 by ptaylor(2198) $\"\"$ $\"About$

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distance(d) equals rate(r) times time(t) or d=rt; t=d/r and r=d/t\r
\n" ); document.write( "\n" ); document.write( "Let t=time that elapses until the two vehicles are 274 mi apart
\n" ); document.write( "When Bus#2 leaves, Bus#1 has already travelled 44*1 or 44 miles\r
\n" ); document.write( "\n" ); document.write( "Distance Bus#1 travels=44+44t
\n" ); document.write( "Distance Bus#2 travels=48t\r
\n" ); document.write( "\n" ); document.write( "Now we are told that the distance Bus#1 travels plus the distance Bus#2 travels equals 274 mi, or:\r
\n" ); document.write( "\n" ); document.write( "44+44t+48t=274 subtract 44 from both sides\r
\n" ); document.write( "\n" ); document.write( "44-44+44t+48t=274-44 collect like terms\r
\n" ); document.write( "\n" ); document.write( "92t=230 divide both sides by 92
\n" ); document.write( "t=2.5 hours------------------------time that elapses until the two vehicles are 274 mi apart\r
\n" ); document.write( "\n" ); document.write( "Bus#2 leaves at 2:00pm. So 2:00pm +2.5 hours=4:30pm the time when the two busses are 274 mi apart\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "44+44*2.5=154 mi
\n" ); document.write( "48*2.5=120
\n" ); document.write( "154+120=274
\n" ); document.write( "274=274\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( "

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