document.write( "Question 6533: Please help me solve $\"b%5E4+%2B+b%5E2+-+20+=+0\"$ \n" ); document.write( "

Algebra.Com's Answer #774131 by Shin123(626) $\"\"$ $\"About$

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Let a=b². Then the equation becomes a²+a-20=0. Factoring leaves $\"%28a%2B5%29%28a-4%29=0\"$ So a=-5 or a=4. So we have $\"b%5E2=-5\"$ and $\"b%5E2=4\"$ So the real solutions are b=2 and b=-2. (Note:The imaginary solutions are $\"b=i%2Aroot%282%2C5%29\"$ and $\"b=-i%2Aroot%282%2C5%29\"$ ). \n" ); document.write( "

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