document.write( "Question 15681: 9x4=25x2 -16
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document.write( "the x is to the 4th power, and the x is 2 the 2nd power , didn't know hot to type these right on the computer/ Its a \"substitution problem so i replaced x squared with a t so i get 9t2 (t squared ) -25t +16. . i cannot figure out how to factor this. \n" );
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Algebra.Com's Answer #7741 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! First of all, you can use the subsitution, but don't LOSE the equation. What you probably mean is this: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This factors into: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Notice that the outer times outer term is -9t, and the inner times inner is -16t, and this adds up to -25t, which is the middle term.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now you have to go back and solve for x, where you made the substitution \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( " |