document.write( "Question 1152115: If P(X) = .23 and P(X and Y) = .12 and P(X or Y) =.34, find the complement of P(Y)? \n" ); document.write( "

Algebra.Com's Answer #774044 by ikleyn(52781) $\"\"$ $\"About$

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document.write( "You are given\r\n" );
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document.write( "    P(X) = 0.23\r\n" );
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document.write( "    P(X and Y) = 0.12\r\n" );
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document.write( "    P(X or Y) = 0.34 = P(X) + P(Y) - P(X and Y) = 0.23 + P(Y) - 0.12.\r\n" );
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document.write( "From the last equation,  \r\n" );
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document.write( "    P(Y) = 0.34 - 0.23 + 0.12 = 0.23.\r\n" );
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document.write( "Then the complement of P(Y) is\r\n" );
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document.write( "    P'(Y) = 1 - P(Y) = 1 - 0.23 = 0.77.    ANSWER\r\n" );
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