document.write( "Question 1152103: Two angles are complementary. The measure of the larger angle is 10 more than 4 times the measure of the smaller angle. Find the measure of both angles. \n" ); document.write( "

Algebra.Com's Answer #774031 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( "complementary angles are two angles whose sum is $\"90\"$ degrees\r
\n" ); document.write( "\n" ); document.write( "let the larger angle be $\"alpha\"$ and the smaller angle $\"beta\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"alpha%2Bbeta=90\"$ .......eq.1\r
\n" ); document.write( "\n" ); document.write( "if the measure of the larger angle is $\"10\"$ more than $\"4\"$ times the measure of the smaller angle, we have\r
\n" ); document.write( "\n" ); document.write( " $\"alpha=4%2Abeta%2B10\"$ ........eq.2-> substitute in eq.1\r
\n" ); document.write( "\n" ); document.write( " $\"4%2Abeta%2B10%2Bbeta=90\"$ .......eq.1\r
\n" ); document.write( "\n" ); document.write( " $\"5%2Abeta=90-10\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"5%2Abeta=80\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"beta=80%2F5\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"beta=16\"$ degrees\r
\n" ); document.write( "\n" ); document.write( "then\r
\n" ); document.write( "\n" ); document.write( " $\"alpha%2Bbeta=90\"$ .......eq.1\r
\n" ); document.write( "\n" ); document.write( " $\"alpha%2B16=90\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"alpha=90-16\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"alpha=74\"$ \r
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