document.write( "Question 106361: help!!! my # is a multiple of 150 -- 9 is a factor of my # -- my # has 3 digits
\n" ); document.write( "the sum of the # in my digit is 9
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Algebra.Com's Answer #77397 by HyperBrain(694)\"\" \"About 
You can put this solution on YOUR website!
It is true that you number is divisible by 9 because the sum of its digits is 9 and a number is divisible by 9 if the sum of the digits is divisible by 9 (9 is divisible by 9)\r
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\n" ); document.write( "\n" ); document.write( "It is a multiple of 150. And, \"150=15%2A10\" this means that it MUST end with a ZERO.\r
\n" ); document.write( "\n" ); document.write( "Aso, \"150=3%2A50\"---it is divisible by 50! that means it is just ending up with 00 or 50.\r
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\n" ); document.write( "\n" ); document.write( "AGAIN, the sum of the digits must be divisible by 9. Now, we know two things the second digit and the last digit---the second digit maybe a FIVE or a ZERO and the last didit is sure to be ZERO.\r
\n" ); document.write( "\n" ); document.write( "The sum maybe\r
\n" ); document.write( "\n" ); document.write( "1st digit+\"0%2B5\"=1st digit +\"5\"\r
\n" ); document.write( "\n" ); document.write( "or\r
\n" ); document.write( "\n" ); document.write( "1st digit + \"0%2B0\"= 1st digit\r
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\n" ); document.write( "\n" ); document.write( "In the first case, there is one solution---450 (a multiple of 150, ends with 50, the sum is \"4%2B5%2B0=9\" which is divisible by 9.\r
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\n" ); document.write( "\n" ); document.write( "In the second case, there is also one solution---90( amultiple of 150, ends with 00, and the sum of the digits is \"9%2B0%2B0=9\" which is divisible by 9.\r
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\n" ); document.write( "\n" ); document.write( "Therefore, your number maybe 450 or 900.\r
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\n" ); document.write( "\n" ); document.write( "Power up,
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