document.write( "Question 106361: help!!! my # is a multiple of 150 -- 9 is a factor of my # -- my # has 3 digits
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document.write( "the sum of the # in my digit is 9 \n" );
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Algebra.Com's Answer #77397 by HyperBrain(694)![]() ![]() ![]() You can put this solution on YOUR website! It is true that you number is divisible by 9 because the sum of its digits is 9 and a number is divisible by 9 if the sum of the digits is divisible by 9 (9 is divisible by 9)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It is a multiple of 150. And, \n" ); document.write( "\n" ); document.write( "Aso, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "AGAIN, the sum of the digits must be divisible by 9. Now, we know two things the second digit and the last digit---the second digit maybe a FIVE or a ZERO and the last didit is sure to be ZERO.\r \n" ); document.write( "\n" ); document.write( "The sum maybe\r \n" ); document.write( "\n" ); document.write( "1st digit+ \n" ); document.write( "\n" ); document.write( "or\r \n" ); document.write( "\n" ); document.write( "1st digit + \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In the first case, there is one solution---450 (a multiple of 150, ends with 50, the sum is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In the second case, there is also one solution---90( amultiple of 150, ends with 00, and the sum of the digits is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, your number maybe 450 or 900.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Power up, \n" ); document.write( "HyperBrain! \n" ); document.write( " |