document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=106373>Question 106373</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with this expression: logA/logB = A/B = 2/3.  The correct answer is 2/3.  It was solved correctly to = 2/3.  The logs were canceled which is not a proper method of using logs.  I need to know what A and B are so that logA/logB = 2/3.  \r<BR>\n" );
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document.write( "I think the problem can be set up to look like: logA = log 2x and logB = log 3x.  So, log2x/log3x = 2x/3x.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77396 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77396\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I need to know what A and B are so that logA/logB = 2/3. <BR>\n" );
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document.write( "The \"change of base rule\" says logA/logB = log(baseB)A<BR>\n" );
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document.write( "So your equation becomes <BR>\n" );
document.write( "log(base B)A = 2/3<BR>\n" );
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document.write( "Writing that in exponential form you get:<BR>\n" );
document.write( "A = B(2/3)<BR>\n" );
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document.write( "Therefore B = A(3/2)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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