document.write( "Question 1151950: Researchers are interested in estimating difference in drug therapy adherence among subjects with depression who received usual care and those who received care in a collaborative care model. The collaborative care model emphasized the role of clinical pharmacists in providing drug therapy management and treatment follow-up. Of the 50 subjects receiving usual care, 34 adhered to the prescribed drug regimen, while 34 out of 74 subjects in the collaborative care model adhered to the drug regimen. Construct a 95% confidence interval for the difference in adherence proportions for the populations of subjects represented by these two samples and interpret the result \n" ); document.write( "
Algebra.Com's Answer #773950 by Boreal(15235)\"\" \"About 
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the half-interval is z*sqrt (p1(1-p1)/n1+p2(1-p2)/n2))
\n" ); document.write( "(34/50) =p1=0.68
\n" ); document.write( "(34/74)=p2=0.459
\n" ); document.write( "SE=sqrt ((0.68*0.32/50+0.459*0.541/74))=sqrt(0.00771)=0.088
\n" ); document.write( "z=1.96
\n" ); document.write( "z*SE=0.172
\n" ); document.write( "95% CI of difference is 0.221 +/- 0.172
\n" ); document.write( "or (0.049, 0.383)\r
\n" ); document.write( "\n" ); document.write( "Because the CI of the difference does NOT contain 0, there is statistical support for a true difference in means between these two proportions, and there is a difference in adherence proportions.\r
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