document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1152045>Question 1152045</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of 2 numbers is 21.3/4 of one of the number is added to 2/3 of the other gives a sum of 15.Find the two numbers.please with step by step explanation.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #773947 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=773947\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> numbers are x and y, and they add to 21 (3/4)  x+y=21 (3/4) so x=21 (3/4)-y<BR>\n" );
document.write( "x+(2/3)y=15<BR>\n" );
document.write( "therefore x=15-(2/3)y<BR>\n" );
document.write( "but from the first, x=21(3/4)-y as well.<BR>\n" );
document.write( "since x equals either, they both equal each other<BR>\n" );
document.write( "15-(2/3)y=21(3/4)-y<BR>\n" );
document.write( "(1/3)y=6 (3/4), and y is 3 times 6 3/4 or 20.25\r<BR>\n" );
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document.write( "If one number is 20.25, the other is 1.5 to add to 21 3/4<BR>\n" );
document.write( "1.5 + (2/3)20.25=1.5+(2/3)*81/4=1/5(54/4)=1.5+13.5=15<BR>\n" );
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