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You can put this solution on YOUR website!
\n" ); document.write( "You have received three responses showing different algebraic solution methods, or the beginnings of algebraic solution methods.
\n" ); document.write( "All three are fine... if an algebraic solution is required.
\n" ); document.write( "If an algebraic solution is not required, then use your common sense to solve the problem quickly by the method shown by tutor @ikleyn.
\n" ); document.write( "Here is a little more on her method, in case it is not clear to you.
\n" ); document.write( "(1) If you know the average of two numbers is x and the two numbers are the same, then obviously the two numbers are x and x.
\n" ); document.write( "(2) If you know the average of two numbers is x and the difference between the two numbers is 2, then take the x and x from example (1) and add 1 to one of them and subtract 1 from the other; the two numbers are x+1 and x-1. The average is then still the same, but now the numbers differ by 2.
\n" ); document.write( "So if you know the average is x and the two numbers differ by 10, then you know one number is 5 more than x and the other is 5 less than x; they are x+5 and x-5.
\n" ); document.write( "Applying the principle to this particular problem, with an average of 11 and a difference of 4, you get what tutor @ikleyn says for the two numbers: 11+2=13 and 11-2=9.
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