document.write( "Question 1152016: Can you prove the following identity algebraically.\r
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Algebra.Com's Answer #773901 by MathLover1(20850)\"\" \"About 
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sec (x) - cos( x) = sin( x) tan( x)\r
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\n" ); document.write( "\n" ); document.write( "manipulate left side:\r
\n" ); document.write( "\n" ); document.write( "\"sec+%28x%29+-+cos%28+x%29\" ...................use identity \"sec+%28x%29+=1%2Fcos%28x%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"1%2Fcos%28x%29+-+cos%28+x%29\"......common denominator is \"cos%28x%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"1%2Fcos%28x%29+-+cos%5E2%28+x%29%2Fcos%28x%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"%281+-+cos%5E2%28+x%29%29%2Fcos%28x%29\".......use identity \"sin%5E2%28x%29%2Bcos%5E2%28x%29=1\"=>\"1+-+cos%5E2%28+x%29=sin%5E2%28x%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"sin%5E2%28+x%29%2Fcos%28x%29\"......write \"sin%5E2%28+x%29\" as \"sin%28+x%29%2Asin%28+x%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"%28+sin%28+x%29%2Ahighlight%28sin%28+x%29%29%29%2Fhighlight%28cos%28x%29%29\".......use identity \"sin%28x%29%2Fcos%28x%29=tan%28x%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"+sin%28+x%29%2Atan%28+x%29\"\r
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