document.write( "Question 15665: find five consecutive odd intergers such that the sum of the first and fifth number is one less than three times the fourth number \n" ); document.write( "
Algebra.Com's Answer #7739 by venugopalramana(3286)\"\" \"About 
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the general expression for odd integer is 2n+1...since ..n is any integer, 2n is always even . if we add one to an even number we get an odd number
\n" ); document.write( " so let the first odd integer be 2n+1
\n" ); document.write( " the second point to be noted is that consecutive odd integers differ by 2 .
\n" ); document.write( " ( like 1,3,5 etc..)..so now
\n" ); document.write( " 1st. number = 2n+1
\n" ); document.write( " 2nd.no.=2n+3
\n" ); document.write( " 3rd.no. = 2n+5
\n" ); document.write( " 4th.no. = 2n+7
\n" ); document.write( " 5th. no. =2n+9
\n" ); document.write( "sum of 1st and 5th. nos .=2n+1+2n+9=4n+10.......(1)\r
\n" ); document.write( "\n" ); document.write( " three times the 4th. no. = 3*(2n+7)=6n+21
\n" ); document.write( " one less than above = 6n+21-1 = 6n+20.....(2)
\n" ); document.write( " (1) = (2) ....so 4n+10=6n+20
\n" ); document.write( " 4n-6n=20-10=10
\n" ); document.write( "-2n=10
\n" ); document.write( "n=-5...so the five nos.are
\n" ); document.write( " 1st. number = 2n+1 = 2(*-5)+1 = -9
\n" ); document.write( " 2nd.no.=2n+3................=-7
\n" ); document.write( " 3rd.no. = 2n+5................=-5
\n" ); document.write( " 4th.no. = 2n+7................=-3
\n" ); document.write( " 5th. no. =2n+9................=-1\r
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