document.write( "Question 1151971: One safe investment pays 7​% per​ year, and a more risky investment pays 14​% per year.\r
\n" ); document.write( "\n" ); document.write( "a. How much must be invested in each account if an investor of ​$100,000 would like a return of ​$9,100 per​ year?
\n" ); document.write( "b. Why might the investor use two accounts rather than put all the money in the 14​% ​investment?\r
\n" ); document.write( "\n" ); document.write( "a. $__ is invested in the 7% account.
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Algebra.Com's Answer #773863 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "Here is an easy alternative to the standard algebraic method (shown by the other tutors) for solving \"mixture\" problems like this.

\n" ); document.write( "(1) The $9,100 return on an investment of $100,000 is a rate of 9.1%.
\n" ); document.write( "(2) That 9.1% is 3/10 of the way from 7% to 14%.
\n" ); document.write( "(Think of starting at 7% on a number line and \"walking\" towards 14%, stopping when you get to 9.1%. What fraction of the distance have you gone? 7% to 14% is a difference of 7%; 7% to 9.1% is a difference of 2.1%. The fraction of the distance you have gone is 2.1/7 = 3/10.)
\n" ); document.write( "(3) Since 9.1% is 3/10 of the way from 7% to 14%, 3/10 of the total was invested at the higher rate.

\n" ); document.write( "ANSWER: 3/10 of $100,000, or $30,000, at 14%; the other 7/10, or $70,000, at 7%.

\n" ); document.write( "CHECK:
\n" ); document.write( ".14(30,000)+.07(70,000) = 4200+4900 = 9100

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