document.write( "Question 1151939: an art museum sold 63 tickets in 30 minutes. The ratio of adult to child tickets was 5:1. The ratio of adult to senior tickets was 5:3. How many of each kind of ticket were sold? \n" ); document.write( "
Algebra.Com's Answer #773815 by ikleyn(52847)![]() ![]() You can put this solution on YOUR website! .\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " It can be solved mentally, without using equations.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "The total tickets is 63.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The ratio of child to adults is 1:5.\r\n" ); document.write( "\r\n" ); document.write( "The ratio of senior to adults is 3:5.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "It means that for every 5 adults there are 1 child and 3 seniors.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Hense, you can group tickets in sets, in a way that every set contain 5 adult tickets, 1 child and 3 senior ticket; \r\n" ); document.write( "in all, 5 + 1 + 3 = 9 tickets in each set.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Then the number of sets is 63/9 = 7.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "ANSWER. 5*7 = 35 adult tickets; 7 child tickets; and 3*7 = 21 senior tickets.\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |